JEE Main 202228 Jul, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002limx→0((x+2cosx)3+2(x+2cosx)2+3sin(x+2cosx)(x+2)3+2(x+2)2+3sin(x+2))100x\lim\limits_{x \rightarrow 0}\left(\frac{(x+2 \cos x)^{3}+2(x+2 \cos x)^{2}+3 \sin (x+2 \cos x)}{(x+2)^{3}+2(x+2)^{2}+3 \sin (x+2)}\right)^{\frac{100}{x}}x→0lim((x+2)3+2(x+2)2+3sin(x+2)(x+2cosx)3+2(x+2cosx)2+3sin(x+2cosx))x100 is equal to ___________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
