Let y = y(x) be the solution of the differential equation, x dy/dx + y = x log e x, (x > 1). If 2y(2) = log e 4 - 1, then y(e) is equal to:

Differential Equations: JEE Main 2019 Mathematics question

JEE Main 2019 · 12 Jan, Morning shift · Q3517

JEE Main 201912 Jan, Morning shiftMathematicsEasyDifferential Equations163× since 2002

Let y = y(x) be the solution of the differential equation, x

{{dy} \over {dx}}

+ y = x log_e x, (x > 1). If 2y(2) = log_e 4

-

1, then y(e) is equal to :

JEE Main 2019 · 12 Jan, Morning shift · Q3517

JEE Main 201912 Jan, Morning shiftMathematicsEasyDifferential Equations163× since 2002

Let y = y(x) be the solution of the differential equation, x

{{dy} \over {dx}}

+ y = x log_e x, (x > 1). If 2y(2) = log_e 4

-

1, then y(e) is equal to :