Differential Equations: JEE Main 2020 Mathematics question

Let y = y(x) be the solution of the differential equation cosx${{dy} \over {dx}}$ + 2ysinx = sin2x, x $\in$ $\left( {0,{\pi \over 2}} \right)$. If y$\left( {{\pi \over 3}} \right)$ = 0, then y$\left( {{\pi \over 4}} \right)$ is equal to :