Differential Equations: JEE Main 2020 Mathematics question

Let y = y(x) be the solution of the differential equation, ${{2 + \sin x} \over {y + 1}}.{{dy} \over {dx}} = - \cos x$, y > 0,y(0) = 1. If y($\pi$) = a and ${{dy} \over {dx}}$ at x = $\pi$ is b, then the ordered pair (a, b) is equal to :