Let y = y(x) be the solution curve of the differential equation, (y² - x)dy/dx = 1, satisfying y(0) = 1. This curve intersects the x-axis at a point whose abscissa is:

Differential Equations: JEE Main 2020 Mathematics question

JEE Main 2020 · 7 Jan, Evening shift · Q3602

JEE Main 20207 Jan, Evening shiftMathematicsMediumDifferential Equations163× since 2002

Let y = y(x) be the solution curve of the differential equation,

\left( {{y^2} - x} \right){{dy} \over {dx}} = 1

, satisfying y(0) = 1. This curve intersects the x-axis at a point whose abscissa is :

JEE Main 2020 · 7 Jan, Evening shift · Q3602

JEE Main 20207 Jan, Evening shiftMathematicsMediumDifferential Equations163× since 2002

Let y = y(x) be the solution curve of the differential equation,

\left( {{y^2} - x} \right){{dy} \over {dx}} = 1

, satisfying y(0) = 1. This curve intersects the x-axis at a point whose abscissa is :