JEE Main 202127 Jul, Morning shiftMathematicsMediumDifferential Equations163× since 2002Let y = y(x) be solution of the differential equation log(dydx)=3x+4y{\log _{}}\left( {{{dy} \over {dx}}} \right) = 3x + 4ylog(dxdy)=3x+4y, with y(0) = 0. If y(−23loge2)=αloge2y\left( { - {2 \over 3}{{\log }_e}2} \right) = \alpha {\log _e}2y(−32loge2)=αloge2, then the value of α\alphaα is equal to :AOption A. −14- {1 \over 4}−41BOption B. 14{1 \over 4}41COption C. 222DOption D. −12- {1 \over 2}−21CheckSkip · show solution
