JEE Main 202126 Aug, Evening shiftMathematicsMediumDifferential Equations163× since 2002
Let y(x) be the solution of the differential equation
2x² dy + (e^y 2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to :
JEE Main 2021 · 26 Aug, Evening shift · Q3615