JEE Main 201911 Jan, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002Let [x] denote the greatest integer less than or equal to x. Then limx→0tan(πsin2x)+(∣x∣−sin(x[x]))2x2\mathop {\lim }\limits_{x \to 0} {{\tan \left( {\pi {{\sin }^2}x} \right) + {{\left( {\left| x \right| - \sin \left( {x\left[ x \right]} \right)} \right)}^2}} \over {{x^2}}}x→0limx2tan(πsin2x)+(∣x∣−sin(x[x]))2AOption A. equals π\piπ + 1BOption B. equals 0COption C. does not existDOption D. equals π\piπCheckSkip · show solution