JEE Main 20204 Sep, Morning shiftMathematicsHardVector Algebra184× since 2002Let x₀ be the point of Local maxima of f(x)=a→.(b→×c→)f(x) = \overrightarrow a .\left( {\overrightarrow b \times \overrightarrow c } \right)f(x)=a.(b×c), where a→=xi^−2j^+3k^\overrightarrow a = x\widehat i - 2\widehat j + 3\widehat ka=xi−2j+3k, b→=−2i^+xj^−k^\overrightarrow b = - 2\widehat i + x\widehat j - \widehat kb=−2i+xj−k, c→=7i^−2j^+xk^\overrightarrow c = 7\widehat i - 2\widehat j + x\widehat kc=7i−2j+xk. Then the value of a→.b→+b→.c→+c→.a→\overrightarrow a .\overrightarrow b + \overrightarrow b .\overrightarrow c + \overrightarrow c .\overrightarrow aa.b+b.c+c.a at x = x₀ is :AOption A. 14BOption B. -30COption C. -4DOption D. -22CheckSkip · show solution
