Coordinate Geometry: JEE Main 2020 Mathematics question

JEE Main 2020 · 4 Sep, Morning shift · Q3756

JEE Main 20204 Sep, Morning shiftMathematicsMediumCoordinate Geometry478× since 2002

Let

{{{x^2}} \over {{a^2}}} + {{{y^2}} \over {{b^2}}} = 1

(a > b) be a given ellipse, length of whose latus rectum is 10. If its eccentricity is the maximum value of the function,

\phi \left( t \right) = {5 \over {12}} + t - {t^2}

, then a² + b² is equal to :

JEE Main 2020 · 4 Sep, Morning shift · Q3756

JEE Main 20204 Sep, Morning shiftMathematicsMediumCoordinate Geometry478× since 2002

Let

{{{x^2}} \over {{a^2}}} + {{{y^2}} \over {{b^2}}} = 1

(a > b) be a given ellipse, length of whose latus rectum is 10. If its eccentricity is the maximum value of the function,

\phi \left( t \right) = {5 \over {12}} + t - {t^2}

, then a² + b² is equal to :

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