JEE Main 202311 Apr, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002Let f(x)=[x2−x]+∣−x+[x]∣f(x)=\left[x^{2}-x\right]+|-x+[x]|f(x)=[x2−x]+∣−x+[x]∣, where x∈Rx \in \mathbb{R}x∈R and [t][t][t] denotes the greatest integer less than or equal to ttt. Then, fff is :AOption A. continuous at x=0x=0x=0, but not continuous at x=1x=1x=1BOption B. continuous at x=0x=0x=0 and x=1x=1x=1COption C. continuous at x=1x=1x=1, but not continuous at x=0x=0x=0DOption D. not continuous at x=0x=0x=0 and x=1x=1x=1CheckSkip · show solution
