JEE Main 202431 Jan, Evening shiftMathematicsMediumVector Algebra184× since 2002Let a⃗=3i^+2j^+k^,b⃗=2i^−j^+3k^\vec{a}=3 \hat{i}+2 \hat{j}+\hat{k}, \vec{b}=2 \hat{i}-\hat{j}+3 \hat{k}a=3i^+2j^+k^,b=2i^−j^+3k^ and c⃗\vec{c}c be a vector such that (a⃗+b⃗)×c⃗=2(a⃗×b⃗)+24j^−6k^(\vec{a}+\vec{b}) \times \vec{c}=2(\vec{a} \times \vec{b})+24 \hat{j}-6 \hat{k}(a+b)×c=2(a×b)+24j^−6k^ and (a⃗−b⃗+i^)⋅c⃗=−3(\vec{a}-\vec{b}+\hat{i}) \cdot \vec{c}=-3(a−b+i^)⋅c=−3. Then ∣c⃗∣2|\vec{c}|^2∣c∣2 is equal to ________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
