JEE Main 202227 Jul, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002Let the minimum value v0v_{0}v0 of v=∣z∣2+∣z−3∣2+∣z−6i∣2,z∈Cv=|z|^{2}+|z-3|^{2}+|z-6 i|^{2}, z \in \mathbb{C}v=∣z∣2+∣z−3∣2+∣z−6i∣2,z∈C is attained at z=z0{ }{z}=z_{0}z=z0. Then ∣2z02−zˉ03+3∣2+v02\left|2 z_{0}^{2}-\bar{z}_{0}^{3}+3\right|^{2}+v_{0}^{2}2z02−zˉ03+32+v02 is equal to :AOption A. 1000BOption B. 1024COption C. 1105DOption D. 1196CheckSkip · show solution
