Let the mean and the variance of 5 observations x₁, x₂, x₃, x₄, x₅ be 24/5 and 194/25 respectively. If the mean and variance of the first 4 observation are 7/2 and a respectively, then (4a + x₅) is equal to:

Statistics and Probability: JEE Main 2022 Mathematics question

JEE Main 2022 · 29 Jun, Morning shift · Q5470

JEE Main 202229 Jun, Morning shiftMathematicsHardStatistics and Probability258× since 2002

Let the mean and the variance of 5 observations x₁, x₂, x₃, x₄, x₅ be

{24 \over 5}

and

{194 \over 25}

respectively. If the mean and variance of the first 4 observation are

{7 \over 2}

and a respectively, then (4a + x₅) is equal to:

JEE Main 2022 · 29 Jun, Morning shift · Q5470

JEE Main 202229 Jun, Morning shiftMathematicsHardStatistics and Probability258× since 2002

Let the mean and the variance of 5 observations x₁, x₂, x₃, x₄, x₅ be

{24 \over 5}

and

{194 \over 25}

respectively. If the mean and variance of the first 4 observation are

{7 \over 2}

and a respectively, then (4a + x₅) is equal to: