JEE Main 202228 Jul, Morning shiftMathematicsMediumMatrices and Determinants245× since 2002Let the matrix A=[010001100]A=\left[\begin{array}{lll}0 & 1 & 0 \\ 0 & 0 & 1 \\ 1 & 0 & 0\end{array}\right]A=001100010 and the matrix B0=A49+2A98B_{0}=A^{49}+2 A^{98}B0=A49+2A98. If Bn=Adj(Bn−1)B_{n}=A d j\left(B_{n-1}\right)Bn=Adj(Bn−1) for all n≥1n \geq 1n≥1, then det(B4)\operatorname{det}\left(B_{4}\right)det(B4) is equal to :AOption A. 3283^{28}328BOption B. 3303^{30}330COption C. 3323^{32}332DOption D. 3363^{36}336CheckSkip · show solution