Let the line (x - 2)/3 = (y - 1)/(- 5) = (z + 2)/2 lie in the plane x + 3y - α z + β = 0. Then (α,β) equals

Three Dimensional Geometry: JEE Main 2009 Mathematics question

JEE Main 2009 · Annual, Paper 1 · Q2391

JEE Main 2009Annual, Paper 1MathematicsMediumThree Dimensional Geometry249× since 2002

Let the line

\,\,\,\,\,

{{x - 2} \over 3} = {{y - 1} \over { - 5}} = {{z + 2} \over 2}

lie in the plane

\,\,\,\,\,

x + 3y - \alpha z + \beta = 0.

Then

\left( {\alpha ,\beta } \right)

equals

JEE Main 2009 · Annual, Paper 1 · Q2391

JEE Main 2009Annual, Paper 1MathematicsMediumThree Dimensional Geometry249× since 2002

Let the line

\,\,\,\,\,

{{x - 2} \over 3} = {{y - 1} \over { - 5}} = {{z + 2} \over 2}

lie in the plane

\,\,\,\,\,

x + 3y - \alpha z + \beta = 0.

Then

\left( {\alpha ,\beta } \right)

equals