Let the line passing through the points P(2,-1,2) and Q(5,3,4) meet the plane x-y+z=4 at the point R. Then the distance of the point R from the plane x+2 y+3 z+2=0 measured parallel to the line (x-7)/2=(y+3)/2=(z-2)/1 is equal to:

Three Dimensional Geometry: JEE Main 2023 Mathematics question

JEE Main 2023 · 11 Apr, Evening shift · Q2609

JEE Main 202311 Apr, Evening shiftMathematicsHardThree Dimensional Geometry249× since 2002

Let the line passing through the points

\mathrm{P}(2,-1,2)

and

\mathrm{Q}(5,3,4)

meet the plane

x-y+z=4

at the point

\mathrm{R}

. Then the distance of the point

\mathrm{R}

from the plane

x+2 y+3 z+2=0

measured parallel to the line

\frac{x-7}{2}=\frac{y+3}{2}=\frac{z-2}{1}

is equal to :