Let the image of the point P (0,-5,0) in the line (x-1)/2=y/1=(z+1)/(-2) be the point R and the image of the point Q (0,(-1)/2,0) in the line (x-1)/(-1)=(y+9)/4=(z+1)/1 be the point S. Then the square of the area of the parallelogram PQRS is _ _ _.

Three Dimensional Geometry: JEE Main 2026 Mathematics question

JEE Main 2026 · 6 Apr, Evening shift · Q24

JEE Main 20266 Apr, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002

Let the image of the point P

(0,-5,0)

in the line

\dfrac{x-1}{2}=\dfrac{y}{1}=\dfrac{z+1}{-2}

be the point R and the image of the point Q

\left(0,\dfrac{-1}{2},0\right)

in the line

\dfrac{x-1}{-1}=\dfrac{y+9}{4}=\dfrac{z+1}{1}

be the point S. Then the square of the area of the parallelogram PQRS is ______.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2026 · 6 Apr, Evening shift · Q24

JEE Main 20266 Apr, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002

Let the image of the point P

(0,-5,0)

in the line

\dfrac{x-1}{2}=\dfrac{y}{1}=\dfrac{z+1}{-2}

be the point R and the image of the point Q

\left(0,\dfrac{-1}{2},0\right)

in the line

\dfrac{x-1}{-1}=\dfrac{y+9}{4}=\dfrac{z+1}{1}

be the point S. Then the square of the area of the parallelogram PQRS is ______.

Your answerType your answer. Integers and decimals are accepted.