JEE Main 20231 Feb, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002Let the image of the point P(2,−1,3)P(2,-1,3)P(2,−1,3) in the plane x+2y−z=0x+2 y-z=0x+2y−z=0 be QQQ. Then the distance of the plane 3x+2y+z+29=03 x+2 y+z+29=03x+2y+z+29=0 from the point QQQ is :AOption A. 2142\sqrt{14}214BOption B. 2227\frac{22\sqrt2}{7}7222COption C. 2427\frac{24\sqrt2}{7}7242DOption D. 3143\sqrt{14}314CheckSkip · show solution