Let the foot of the perpendicular from the point (1, 2, 4) on the line (x + 2)/4 = (y - 1)/2 = (z + 1)/3 be P. Then the distance of P from the plane 3x + 4y + 12z + 23 = 0 is:

Three Dimensional Geometry: JEE Main 2022 Mathematics question

JEE Main 2022 · 27 Jun, Evening shift · Q2444

JEE Main 202227 Jun, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002

Let the foot of the perpendicular from the point (1, 2, 4) on the line

{{x + 2} \over 4} = {{y - 1} \over 2} = {{z + 1} \over 3}

be P. Then the distance of P from the plane

3x + 4y + 12z + 23 = 0

is :

JEE Main 2022 · 27 Jun, Evening shift · Q2444

JEE Main 202227 Jun, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002

Let the foot of the perpendicular from the point (1, 2, 4) on the line

{{x + 2} \over 4} = {{y - 1} \over 2} = {{z + 1} \over 3}

be P. Then the distance of P from the plane

3x + 4y + 12z + 23 = 0

is :