Let T and C respectively be the transverse and conjugate axes of the hyperbola 16x² - y² + 64x + 4y + 44 = 0. Then the area of the region above the parabola x² = y + 4, below the transverse axis T and on the right of the conjugate axis C is:

Coordinate Geometry: JEE Main 2023 Mathematics question

JEE Main 2023 · 25 Jan, Evening shift · Q3946

JEE Main 202325 Jan, Evening shiftMathematicsMediumCoordinate Geometry478× since 2002

Let T and C respectively be the transverse and conjugate axes of the hyperbola

16{x^2} - {y^2} + 64x + 4y + 44 = 0

. Then the area of the region above the parabola

{x^2} = y + 4

, below the transverse axis T and on the right of the conjugate axis C is :

JEE Main 2023 · 25 Jan, Evening shift · Q3946

JEE Main 202325 Jan, Evening shiftMathematicsMediumCoordinate Geometry478× since 2002

Let T and C respectively be the transverse and conjugate axes of the hyperbola

16{x^2} - {y^2} + 64x + 4y + 44 = 0

. Then the area of the region above the parabola

{x^2} = y + 4

, below the transverse axis T and on the right of the conjugate axis C is :