JEE Main 201912 Jan, Morning shiftMathematicsEasySequence and Series179× since 2002Let S_k = 1+2+3+....+kk.{{1 + 2 + 3 + .... + k} \over k}.k1+2+3+....+k. If S12+S22+..... +S102=512S_1^2 + S_2^2 + .....\, + S_{10}^2 = {5 \over {12}}S12+S22+.....+S102=125A, then A is equal to :AOption A. 283BOption B. 156COption C. 301DOption D. 303CheckSkip · show solution