Let S = 1/(25!) + 1/(3! 23!) + 1/(5! 21!) + up to 13 terms. If 13S = (2^(k))/(n!), k N, then n + k is equal to

Binomial Theorem and Its Simple Applications: JEE Main 2026 Mathematics question

JEE Main 2026 · 24 Jan, Morning shift · Q11

JEE Main 202624 Jan, Morning shiftMathematicsEasyBinomial Theorem and Its Simple Applications131× since 2002

Let

S = \frac{1}{25!} + \frac{1}{3!\,23!} + \frac{1}{5!\,21!} + \ldots

up to 13 terms. If

13S = \frac{2^k}{n!}

k \in \mathbb{N}

, then

n + k

is equal to

JEE Main 2026 · 24 Jan, Morning shift · Q11

JEE Main 202624 Jan, Morning shiftMathematicsEasyBinomial Theorem and Its Simple Applications131× since 2002

Let

S = \frac{1}{25!} + \frac{1}{3!\,23!} + \frac{1}{5!\,21!} + \ldots

up to 13 terms. If

13S = \frac{2^k}{n!}

k \in \mathbb{N}

, then

n + k

is equal to