JEE Main 201910 Jan, Morning shiftMathematicsEasyIntegral Calculus369× since 2002Let I=∫ab(x4−2x2)dx.{\rm I} = \int\limits_a^b {\left( {{x^4} - 2{x^2}} \right)} dx.I=a∫b(x4−2x2)dx. If I is minimum then the ordered pair (a, b) is -AOption A. (2,−2)\left( {\sqrt 2 , - \sqrt 2 } \right)(2,−2)BOption B. (0,2)\left( {0,\sqrt 2 } \right)(0,2)COption C. (−2,2)\left( { - \sqrt 2 ,\sqrt 2 } \right)(−2,2)DOption D. (−2,0)\left( { - \sqrt 2 ,0} \right)(−2,0)CheckSkip · show solution
