Let PQR be a triangle. The points A, B and C are on the sides QR, RP and PQ respectively such that QA/AR = RB/BP = PC/CQ = 1/2. Then (Area(Δ PQR))/(Area(Δ ABC)) is equal to:

Vector Algebra: JEE Main 2023 Mathematics question

JEE Main 2023 · 24 Jan, Morning shift · Q5697

JEE Main 202324 Jan, Morning shiftMathematicsHardVector Algebra184× since 2002

Let PQR be a triangle. The points A, B and C are on the sides QR, RP and PQ respectively such that

{{QA} \over {AR}} = {{RB} \over {BP}} = {{PC} \over {CQ}} = {1 \over 2}

. Then

{{Area(\Delta PQR)} \over {Area(\Delta ABC)}}

is equal to :

JEE Main 2023 · 24 Jan, Morning shift · Q5697

JEE Main 202324 Jan, Morning shiftMathematicsHardVector Algebra184× since 2002

Let PQR be a triangle. The points A, B and C are on the sides QR, RP and PQ respectively such that

{{QA} \over {AR}} = {{RB} \over {BP}} = {{PC} \over {CQ}} = {1 \over 2}

. Then

{{Area(\Delta PQR)} \over {Area(\Delta ABC)}}

is equal to :