Let p, q and r be real numbers (p ≠ q, r ≠ 0), such that the roots of the equation 1/(x + p) + 1/(x + q) = 1/r are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to:

Complex Numbers and Quadratic Equations: JEE Main 2018 Mathematics question

JEE Main 2018 · 16 Apr, Morning shift · Q5129

JEE Main 201816 Apr, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002

Let p, q and r be real numbers (p

\ne

q, r

\ne

0), such that the roots of the equation

{1 \over {x + p}} + {1 \over {x + q}} = {1 \over r}

are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to :