Coordinate Geometry: JEE Main 2026 Mathematics question

JEE Main 2026 · 5 Apr, Morning shift · Q10

JEE Main 20265 Apr, Morning shiftMathematicsEasyCoordinate Geometry478× since 2002

Let P be a moving point on the circle

x^2 + y^2 - 6x - 8y + 21 = 0

. Then, the maximum distance of P from the vertex of the parabola

x^2 + 6x + y + 13 = 0

is equal to:

JEE Main 2026 · 5 Apr, Morning shift · Q10

JEE Main 20265 Apr, Morning shiftMathematicsEasyCoordinate Geometry478× since 2002

Let P be a moving point on the circle

x^2 + y^2 - 6x - 8y + 21 = 0

. Then, the maximum distance of P from the vertex of the parabola

x^2 + 6x + y + 13 = 0

is equal to:

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