JEE Main 202427 Jan, Morning shiftMathematicsMediumVector Algebra184× since 2002Let a→=i^+2j^+k^,\overrightarrow{\mathrm{a}}=\hat{i}+2 \hat{j}+\hat{k},a=i^+2j^+k^, b→=3(i^−j^+k^)\overrightarrow{\mathrm{b}}=3(\hat{i}-\hat{j}+\hat{k})b=3(i^−j^+k^). Let c→\overrightarrow{\mathrm{c}}c be the vector such that a→×c→=b→\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{c}}=\overrightarrow{\mathrm{b}}a×c=b and a⃗⋅c⃗=3\vec{a} \cdot \vec{c}=3a⋅c=3. Then a⃗⋅((c⃗×b⃗)−b⃗−c⃗)\vec{a} \cdot((\vec{c} \times \vec{b})-\vec{b}-\vec{c})a⋅((c×b)−b−c) is equal to :AOption A. 32BOption B. 36COption C. 24DOption D. 20CheckSkip · show solution
