JEE Main 2010Annual, Paper 1MathematicsHardVector Algebra184× since 2002Let a→=j^−k^\overrightarrow a = \widehat j - \widehat ka=j−k and c→=i^−j^−k^.\overrightarrow c = \widehat i - \widehat j - \widehat k.c=i−j−k. Then the vector b→\overrightarrow bb satisfying a→×b→+c→=0→\overrightarrow a \times \overrightarrow b + \overrightarrow c = \overrightarrow 0a×b+c=0 and a→.b→=3\overrightarrow a .\overrightarrow b = 3a.b=3 :AOption A. 2i^−j^+2k^2\widehat i - \widehat j + 2\widehat k2i−j+2kBOption B. i^−j^−2k^\widehat i - \widehat j - 2\widehat ki−j−2kCOption C. i^+j^−2k^\widehat i + \widehat j - 2\widehat ki+j−2kDOption D. −i^+j^−2k^-\widehat i +\widehat j - 2\widehat k−i+j−2kCheckSkip · show solution
