JEE Main 201816 Apr, Morning shiftMathematicsHardVector Algebra184× since 2002Let a→=i^+j^+k^,c→=j^−k^\overrightarrow a = \widehat i + \widehat j + \widehat k,\overrightarrow c = \widehat j - \widehat ka=i+j+k,c=j−k and a vector b→\overrightarrow bb be such that a→×b→=c→\overrightarrow a \times \overrightarrow b = \overrightarrow ca×b=c and a→.b→=3.\overrightarrow a .\overrightarrow b = 3.a.b=3. Then ∣b→∣\left| {\overrightarrow b } \right|b equals :AOption A. 113{{11} \over 3}311BOption B. 113{{11} \over {\sqrt 3 }}311COption C. 113\sqrt {{{11} \over 3}}311DOption D. 113{{\sqrt {11} } \over 3}311CheckSkip · show solution
