JEE Main 202127 Jul, Morning shiftMathematicsHardVector Algebra184× since 2002Let a→=i^+j^+2k^\overrightarrow a = \widehat i + \widehat j + 2\widehat ka=i+j+2k and b→=−i^+2j^+3k^\overrightarrow b = - \widehat i + 2\widehat j + 3\widehat kb=−i+2j+3k. Then the vector product (a→+b→)×((a→×((a→−b→)×b→))×b→)\left( {\overrightarrow a + \overrightarrow b } \right) \times \left( {\left( {\overrightarrow a \times \left( {\left( {\overrightarrow a - \overrightarrow b } \right) \times \overrightarrow b } \right)} \right) \times \overrightarrow b } \right)(a+b)×((a×((a−b)×b))×b) is equal to :AOption A. 5(34i^−5j^+3k^)5(34\widehat i - 5\widehat j + 3\widehat k)5(34i−5j+3k)BOption B. 7(34i^−5j^+3k^)7(34\widehat i - 5\widehat j + 3\widehat k)7(34i−5j+3k)COption C. 7(30i^−5j^+7k^)7(30\widehat i - 5\widehat j + 7\widehat k)7(30i−5j+7k)DOption D. 5(30i^−5j^+7k^)5(30\widehat i - 5\widehat j + 7\widehat k)5(30i−5j+7k)CheckSkip · show solution