JEE Main 202325 Jan, Evening shiftMathematicsMediumVector Algebra184× since 2002Let a→=−i^−j^+k^,a→ . b→=1\overrightarrow a = - \widehat i - \widehat j + \widehat k,\overrightarrow a \,.\,\overrightarrow b = 1a=−i−j+k,a.b=1 and a→×b→=i^−j^\overrightarrow a \times \overrightarrow b = \widehat i - \widehat ja×b=i−j. Then a→−6b→\overrightarrow a - 6\overrightarrow ba−6b is equal to :AOption A. 3(i^+j^+k^)3\left( {\widehat i + \widehat j + \widehat k} \right)3(i+j+k)BOption B. 3(i^−j^−k^)3\left( {\widehat i - \widehat j - \widehat k} \right)3(i−j−k)COption C. 3(i^+j^−k^)3\left( {\widehat i + \widehat j - \widehat k} \right)3(i+j−k)DOption D. 3(i^−j^+k^)3\left( {\widehat i - \widehat j + \widehat k} \right)3(i−j+k)CheckSkip · show solution
