JEE Main 20208 Jan, Evening shiftMathematicsHardVector Algebra184× since 2002Let a→=i^−2j^+k^\overrightarrow a = \widehat i - 2\widehat j + \widehat ka=i−2j+k and b→=i^−j^+k^\overrightarrow b = \widehat i - \widehat j + \widehat kb=i−j+k be two vectors. If c→\overrightarrow cc is a vector such that b→×c→=b→×a→\overrightarrow b \times \overrightarrow c = \overrightarrow b \times \overrightarrow ab×c=b×a and c→.a→=0\overrightarrow c .\overrightarrow a = 0c.a=0, then c→.b→\overrightarrow c .\overrightarrow bc.b is equal toAOption A. −12- {1 \over 2}−21BOption B. −32- {3 \over 2}−23COption C. 12{1 \over 2}21DOption D. -1CheckSkip · show solution