Let one root of the quadratic equation in x: (k²-15k+27)x²+9(k-1)x+18=0 be twice the other. Then the length of the latus rectum of the parabola y²=6kx is equal to:

Complex Numbers and Quadratic Equations: JEE Main 2026 Mathematics question

JEE Main 2026 · 6 Apr, Morning shift · Q2

JEE Main 20266 Apr, Morning shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002

Let one root of the quadratic equation in

x

(k^2-15k+27)x^2+9(k-1)x+18=0

be twice the other. Then the length of the latus rectum of the parabola

y^2=6kx

is equal to:

JEE Main 2026 · 6 Apr, Morning shift · Q2

JEE Main 20266 Apr, Morning shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002

Let one root of the quadratic equation in

x

(k^2-15k+27)x^2+9(k-1)x+18=0

be twice the other. Then the length of the latus rectum of the parabola

y^2=6kx

is equal to: