JEE Main 20265 Apr, Evening shiftMathematicsEasyVector Algebra184× since 2002Let O be the origin, OP⃗=a⃗\vec{OP}=\vec aOP=a and OQ⃗=b⃗\vec{OQ}=\vec bOQ=b. If R is the point on OP⃗\vec{OP}OP such that OP⃗=5OR⃗\vec{OP}=5\vec{OR}OP=5OR, and M is the point such that OQ⃗=5RM⃗\vec{OQ}=5\vec{RM}OQ=5RM, then PM⃗\vec{PM}PM is equal to :AOption A. 15(a⃗−4b⃗)\frac15\left(\vec a-4\vec b\right)51(a−4b)BOption B. 15(b⃗−4a⃗)\frac15\left(\vec b-4\vec a\right)51(b−4a)COption C. 15(−a⃗+4b⃗)\frac15\left(-\vec a+4\vec b\right)51(−a+4b)DOption D. 15(−b⃗+4a⃗)\frac15\left(-\vec b+4\vec a\right)51(−b+4a)CheckSkip · show solution
