JEE Main 20198 Apr, Morning shiftMathematicsMediumCoordinate Geometry478× since 2002Let O(0, 0) and A(0, 1) be two fixed points. Then the locus of a point P such that the perimeter of Δ\DeltaΔAOP is 4, is :AOption A. 9x² + 8y² – 8y = 16BOption B. 8x² – 9y² + 9y = 18COption C. 8x² + 9y² – 9y = 18DOption D. 9x² – 8y² + 8y = 16CheckSkip · show solution