JEE Main 202127 Jul, Evening shiftMathematicsEasySets, Relations and Functions168× since 2002Let N be the set of natural numbers and a relation R on N be defined by R={(x,y)∈N×N:x3−3x2y−xy2+3y3=0}R = \{ (x,y) \in N \times N:{x^3} - 3{x^2}y - x{y^2} + 3{y^3} = 0\}R={(x,y)∈N×N:x3−3x2y−xy2+3y3=0}. Then the relation R is :AOption A. symmetric but neither reflexive nor transitiveBOption B. reflexive but neither symmetric nor transitiveCOption C. reflexive and symmetric, but not transitiveDOption D. an equivalence relationCheckSkip · show solution
