Limit, Continuity and Differentiability: JEE Main 2018 Mathematics question

JEE Main 2018 · 16 Apr, Morning shift · Q2638

JEE Main 201816 Apr, Morning shiftMathematicsHardLimit, Continuity and Differentiability420× since 2002

Let M and m be respectively the absolute maximum and the absolute minimum values of the function, f(x) = 2x³

-

9x² + 12x + 5 in the interval [0, 3]. Then M

-

m is equal to :

JEE Main 2018 · 16 Apr, Morning shift · Q2638

JEE Main 201816 Apr, Morning shiftMathematicsHardLimit, Continuity and Differentiability420× since 2002

Let M and m be respectively the absolute maximum and the absolute minimum values of the function, f(x) = 2x³

-

9x² + 12x + 5 in the interval [0, 3]. Then M

-

m is equal to :

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