JEE Main 20245 Apr, Evening shiftMathematicsHardSets, Relations and Functions168× since 2002Let f,g:R→Rf, g: \mathbf{R} \rightarrow \mathbf{R}f,g:R→R be defined as : f(x)=∣x−1∣ and g(x)={ex,x≥0x+1,x≤0.f(x)=|x-1| \text { and } g(x)= \begin{cases}\mathrm{e}^x, & x \geq 0 \\ x+1, & x \leq 0 .\end{cases}f(x)=∣x−1∣ and g(x)={ex,x+1,x≥0x≤0. Then the function f(g(x))f(g(x))f(g(x)) isAOption A. neither one-one nor onto.BOption B. one-one but not onto.COption C. both one-one and onto.DOption D. onto but not one-one.CheckSkip · show solution
