JEE Main 202624 Jan, Evening shiftMathematicsMediumCoordinate Geometry478× since 2002Let (h,k)(h,k)(h,k) lie on the circle C:x2+y2=4C: x^2+y^2=4C:x2+y2=4 and the point (2h+1, 3k+2)(2h+1,\,3k+2)(2h+1,3k+2) lie on an ellipse with eccentricity eee. Then the value of 5e2\frac{5}{e^2}e25 is equal to ______.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
