Let (a+b x+c x²)¹⁰=Σ i=0 ²⁰ p i xⁱ, a, b, c N. If p₁=20 and p₂=210, then 2(a+b+c) is equal to:

Binomial Theorem and Its Simple Applications: JEE Main 2023 Mathematics question

JEE Main 2023 · 15 Apr, Morning shift · Q2958

JEE Main 202315 Apr, Morning shiftMathematicsHardBinomial Theorem and Its Simple Applications131× since 2002

Let

\left(a+b x+c x^{2}\right)^{10}=\sum\limits_{i=0}^{20} p_{i} x^{i}, a, b, c \in \mathbb{N}

. If

p_{1}=20

and

p_{2}=210

, then

2(a+b+c)

is equal to :

JEE Main 2023 · 15 Apr, Morning shift · Q2958

JEE Main 202315 Apr, Morning shiftMathematicsHardBinomial Theorem and Its Simple Applications131× since 2002

Let

\left(a+b x+c x^{2}\right)^{10}=\sum\limits_{i=0}^{20} p_{i} x^{i}, a, b, c \in \mathbb{N}

. If

p_{1}=20

and

p_{2}=210

, then

2(a+b+c)

is equal to :