JEE Main 202623 Jan, Evening shiftMathematicsEasySequence and Series179× since 2002Let ∑k=1nak=αn2+βn\sum_{k=1}^{n}a_k=\alpha n^2+\beta n∑k=1nak=αn2+βn. If a10=59a_{10}=59a10=59 and a6=7a1a_6=7a_1a6=7a1, then α+β\alpha+\betaα+β is equal toAOption A. 7BOption B. 3COption C. 12DOption D. 5CheckSkip · show solution
