JEE Main 202228 Jul, Evening shiftMathematicsMediumIntegral Calculus369× since 2002Let In(x)=∫0x1(t2+5)ndt,n=1,2,3,….I_{n}(x)=\int_{0}^{x} \frac{1}{\left(t^{2}+5\right)^{n}} d t, n=1,2,3, \ldots .In(x)=∫0x(t2+5)n1dt,n=1,2,3,…. Then :AOption A. 50I6−9I5=xI5′50 I_{6}-9 I_{5}=x I_{5}^{\prime}50I6−9I5=xI5′BOption B. 50I6−11I5=xI5′50 I_{6}-11 I_{5}=x I_{5}^{\prime}50I6−11I5=xI5′COption C. 50I6−9I5=I5′50 I_{6}-9 I_{5}=I_{5}^{\prime}50I6−9I5=I5′DOption D. 50I6−11I5=I5′50 I_{6}-11 I_{5}=I_{5}^{\prime}50I6−11I5=I5′CheckSkip · show solution
