JEE Main 202313 Apr, Evening shiftMathematicsMediumMatrices and Determinants245× since 2002Let for A=[123α31112],∣A∣=2A = \left[ {\matrix{ 1 & 2 & 3 \cr \alpha & 3 & 1 \cr 1 & 1 & 2 \cr } } \right],|A| = 2A=1α1231312,∣A∣=2. If ∣2 adj (2 adj (2A))∣=32n\mathrm{|2\,adj\,(2\,adj\,(2A))| = {32^n}}∣2adj(2adj(2A))∣=32n, then 3n+α3n + \alpha3n+α is equal toAOption A. 11BOption B. 9COption C. 12DOption D. 10CheckSkip · show solution