JEE Main 202226 Jul, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002Let f(x)={x3−x2+10x−7,x≤1−2x+log2(b2−4),x>1f(x) = \left\{ {\matrix{ {{x^3} - {x^2} + 10x - 7,} & {x \le 1} \cr { - 2x + {{\log }_2}({b^2} - 4),} & {x > 1} \cr } } \right.f(x)={x3−x2+10x−7,−2x+log2(b2−4),x≤1x>1. Then the set of all values of b, for which f(x) has maximum value at x = 1, is :AOption A. (−-−6, −-−2)BOption B. (2, 6)COption C. [−6,−2)∪(2,6][ - 6, - 2) \cup (2,6][−6,−2)∪(2,6]DOption D. [−6,−2)∪(2,6]\left[ {-\sqrt 6 , - 2} \right) \cup \left( {2,\sqrt 6 } \right][−6,−2)∪(2,6]CheckSkip · show solution
