JEE Main 202324 Jan, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002Let f(x)={x2sin(1x), x≠00, x=0f(x) = \left\{ {\matrix{ {{x^2}\sin \left( {{1 \over x}} \right)} & {,\,x \ne 0} \cr 0 & {,\,x = 0} \cr } } \right.f(x)={x2sin(x1)0,x=0,x=0 Then at x=0x=0x=0AOption A. fff is continuous but f′f'f′ is not continuousBOption B. fff and f′f'f′ both are continuousCOption C. fff is continuous but not differentiableDOption D. f′f'f′ is continuous but not differentiableCheckSkip · show solution