JEE Main 201815 Apr, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002Let f(x) = {(x−1)12−x,x>1,x≠2k ,x=2\left\{ {\matrix{ {{{\left( {x - 1} \right)}^{{1 \over {2 - x}}}},} & {x > 1,x \ne 2} \cr {k\,\,\,\,\,\,\,\,\,\,\,\,\,\,} & {,x = 2} \cr } } \right.{(x−1)2−x1,kx>1,x=2,x=2 Thevaue of k for which f s continuous at x = 2 is :AOption A. 1BOption B. eCOption C. e⁻¹DOption D. e⁻²CheckSkip · show solution
