JEE Main 20248 Apr, Evening shiftMathematicsMediumSets, Relations and Functions168× since 2002Let f(x)={−a if −a≤x≤0x+a if 0<x≤af(x)=\left\{\begin{array}{ccc}-\mathrm{a} & \text { if } & -\mathrm{a} \leq x \leq 0 \\ x+\mathrm{a} & \text { if } & 0< x \leq \mathrm{a}\end{array}\right.f(x)={−ax+a if if −a≤x≤00<x≤a where a>0\mathrm{a}> 0a>0 and g(x)=(f(∣x∣)−∣f(x)∣)/2\mathrm{g}(x)=(f(|x|)-|f(x)|) / 2g(x)=(f(∣x∣)−∣f(x)∣)/2. Then the function g:[−a,a]→[−a,a]g:[-a, a] \rightarrow[-a, a]g:[−a,a]→[−a,a] isAOption A. neither one-one nor onto.BOption B. both one-one and onto.COption C. one-one.DOption D. ontoCheckSkip · show solution
