Let f(x)= x³+8; x<0, x²-4; x≥0, and g(x)= (x-8)^(1/3); x<0, (x+4)^(1/2); x≥0. Then the number of points, where the function gof is discontinuous, is _ _ _.

Limit, Continuity and Differentiability: JEE Main 2026 Mathematics question

JEE Main 2026 · 6 Apr, Evening shift · Q25

JEE Main 20266 Apr, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

Let

f(x)=\begin{cases}x^3+8; & x<0,\\ x^2-4; & x\ge0,\end{cases}

and

g(x)=\begin{cases}(x-8)^{1/3}; & x<0,\\ (x+4)^{1/2}; & x\ge0.\end{cases}

Then the number of points, where the function

gof

is discontinuous, is ______.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2026 · 6 Apr, Evening shift · Q25

JEE Main 20266 Apr, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

Let

f(x)=\begin{cases}x^3+8; & x<0,\\ x^2-4; & x\ge0,\end{cases}

and

g(x)=\begin{cases}(x-8)^{1/3}; & x<0,\\ (x+4)^{1/2}; & x\ge0.\end{cases}

Then the number of points, where the function

gof

is discontinuous, is ______.

Your answerType your answer. Integers and decimals are accepted.