JEE Main 20268 Apr, Evening shiftMathematicsEasyIntegral Calculus369× since 2002Let f(x)={13,x≤π2b(1−sinx)(π−2x)2,x>π2f(x)=\begin{cases}\frac{1}{3}, & x\le\frac{\pi}{2}\\ \frac{b(1-\sin x)}{(\pi-2x)^2}, & x>\frac{\pi}{2}\end{cases}f(x)={31,(π−2x)2b(1−sinx),x≤2πx>2π. If fff is continuous at x=π/2x=\pi/2x=π/2, then the value of ∫03b−6∣x2+2x−3∣ dx\int_0^{3b-6}|x^2+2x-3|\,dx∫03b−6∣x2+2x−3∣dx is:AOption A. 5BOption B. 2COption C. 3DOption D. 4CheckSkip · show solution
